Hello readers, welcome back, here is another simple python program which checks whether a number is an Armstrong number or not.

Generally, a number is said to be an Armstrong number if the sum of cubes of the digits is equal to its original number.

For Example, 153 is an Armstrong number as its sum of cubes of each digit 1^{3} + 5^{3} + 3^{3} = 153 whereas 456 is not as its sum of cubes of each digit is not 456.

**You can watch the video on YouTube here.**

#### Armstrong number – Code Visualization

#### Task :

Python program to check an integer number is an Armstrong number or not.

#### Approach :

- Read an input number using
`input()`

or`raw_input()`

. - Check whether the value entered is integer or not.
- Check input_num is greater than 0.
- Initialise a variable named
`arm_num`

to 0. - Find
`remainder`

of the input number by using mod (%) operator to get each digit in the number. - Now cube each digit and add it to
`arm_num`

. - Floor Divide the number by 10.
- Repeat steps 5. 6. 7 until the the input_num is not greater than 0.
- If
`input_num`

is equal to`arm_num`

, print number is ARMSTRONG. - When
`input_num`

is not equals to`arm_num`

, the number is NOT an Armstrong number.

#### Program :

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input_num = (input("Enter any number: ")) try: arm_num = 0 val = int(input_num) while val > 0: reminder = val % 10 arm_num += reminder ** 3 val //= 10 if int(input_num) == arm_num: print(input_num, 'is an ARMSTRONG number') else: print(input_num, 'is NOT an armstrong number') except ValueError: print("That's not a valid number, Try Again !") |