Python Program to print pattern of letter S

Hello everyone! Welcome back to programminginpython.com. I am continuing with this pattern programming series, here I will tell you how to print the pattern of the letter S. In the previous tutorials, I have shown you the patterns of letters A to R. Here it’s now time for Pattern S. You can check the complete series on letter patterns here.

Program on GitHub

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Print Pattern S – Code Visualization

Task:

Python program to print the pattern of letter S

Approach:

• Read an input integer for asking the size of the letter using input()
• Check if the entered number is greater than 8,
  • if yes, call the function print_pattern()
  • else, show a message to enter a number that is greater or equal to 8
• print_pattern()
  • here we only do two things, print star(*) and print space( ), just writing conditions so the pattern of *‘s and ‘s will display the pattern O
  • following are 5 conditions for printing *’s
    We have 2 loops, an outer loop() for rows, and an inner loop for columns
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      # Outer for loop

      for row in range(n):

      # Inner for loop

      for column in range(n):

      # Outer for loop for row in range(n): # Inner for loop for column in range(n):

      # Outer for loop 
      for row in range(n): 
      
          # Inner for loop 
          for column in range(n):

      • Print first row
        • row == 0 and column != 0 and column != n - 1
          row == 0 and column != 0 and column != n - 1
      • Print first column
        • column == 0 and row != 0 and row < n//2
          column == 0 and row != 0 and row < n//2
      • Print middle row
        • row == n//2 and column != n-1 and column != 0
          row == n//2 and column != n-1 and column != 0
      • Print last column
        • column == n-1 and row > n//2 and row != n-1
          column == n-1 and row > n//2 and row != n-1
      • Print last row
        • row == n-1 and column != 0 and column != n - 1
          row == n-1 and column != 0 and column != n - 1
      • print ` ` in remaining all cases.

Program on GitHub

Program:

__author__ = 'Avinash'

# Python3 program to print alphabet pattern S

#   * * * * * * *
# *
# *
# *
#   * * * * * * *
#                 *
#                 *
#                 *
#   * * * * * * *


def print_pattern(n):
    for row in range(n):
        for column in range(n):
            if (
                    # first row
                    (row == 0 and column != 0 and column != n - 1) or

                    # first column
                    (column == 0 and row != 0 and row < n//2) or

                    # middle row
                    (row == n//2 and column != n-1 and column != 0) or

                    # last column
                    (column == n-1 and row > n//2 and row != n-1) or

                    # last row
                    (row == n-1 and column != 0 and column != n - 1)
            ):
                print("*", end=" ")
            else:
                print(" ", end=" ")
        print()

size = int(input("Enter any size: \t"))

if size < 8:
    print("Enter a size minimum of 8")
else:
    print_pattern(size)

Output:

Program on Github