Python Program to print pattern of Letter E

Hello everyone! Welcome back to programminginpython.com. I am continuing with this pattern programming series, here I will tell you how to print the pattern of the letter E. In the previous tutorials, I have shown you the pattern for the letter D, letter C, letter A, and letter B. Here it’s now time for Pattern E.

Program on GitHub

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Print Pattern of Letter E – Code Visualization

Task:

Python program to print the pattern of letter ‘E’

Approach:

• • Read an input integer for asking the size of the letter using input()
  • Check if the entered number is greater than 8,
    • if yes, call the function print_pattern()
    • else, show a message to enter a number which is greater or equal to 8
  • print_pattern()
    • here we only do two things, print star(*) and print space( ), just writing conditions so the pattern of *‘s and ‘s will display the pattern ‘E’
    • following are 3 conditions for printing *’s
      We have 2 loops, outer loop() for rows and inner loop for columns.
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      # Outer for loop

      for row in range(n):

      # Inner for loop

      for column in range(n - 2):

      # Outer for loop for row in range(n): # Inner for loop for column in range(n - 2):

      # Outer for loop
          for row in range(n): 
              # Inner for loop 
              for column in range(n - 2):

    • Print first and last row and middle row
      
      ((row == 0 or row == n-1 or row == n//2 )
      ((row == 0 or row == n-1 or row == n//2 )
    • Print first column
      
      column == 0
      column == 0

• print in remaining all cases.

Program on GitHub

Program:

__author__ = 'Avinash'

# Python3 program to print alphabet E pattern
# *********
# *
# *
# *
# *********
# *
# *
# *********


def print_pattern(n):
    # Outer for loop for number of rows
    for row in range(n):
        # Inner for loop columns
        for column in range(n):
            # prints first and last and middle row
            if ((row == 0 or row == n - 1 or row == n // 2) or
                    # prints first column
                    column == 0):
                print("*", end="")
            else:
                print(" ", end="")
        print()


size = int(input("Enter size: \t"))
if size < 8:
    print("Enter a size greater than 8")
else:
    print_pattern(size)

Output:

Program on GitHub