Python Program to check Armstrong number or not

Hello readers, welcome back to programminginpython.com, here in this post I am going to share with you another simple Python program that checks whether a number is an Armstrong number or not. So let’s code a program in python to check armstrong number.

Generally, a number is said to be an Armstrong number if an n -digit number equals the sum of the nth powers of its digits.

For Example, 153 is an Armstrong number as its sum of cubes of each digit 1³ + 5³ + 3³ = 153 whereas 456 is not as its sum of cubes of each digit is not 456.

You can watch the video on YouTube here.

Program on GitHub

Task :

Python program to check an integer number is an Armstrong number or not.

Approach :

1. Read an input number using input() or raw_input().
2. Check whether the value entered is an integer or not.
3. Check input_num is greater than 0.
4. Initialize a variable named arm_num to 0.
5. Find remainder of the input number by using mod (%) operator to get each digit in the number.
6. Now cube each digit and add it to arm_num.
7. Floor Divide the number by 10.
8. Repeat steps 5. 6. 7 until the input_num is not greater than 0.
9. If input_num is equal to arm_num, print number is ARMSTRONG.
10. When input_num is not equals to arm_num, the number is NOT an Armstrong number.

Program on Github

Program :

__author__ = 'Avinash'

input_num = (input("Enter any number: "))
digit_len = len(str(input_num))

try:
    arm_num = 0
    val = int(input_num)
    while val > 0:
        reminder = val % 10
        arm_num += reminder ** digit_len
        val //= 10

    if int(input_num) == arm_num:
        print(input_num, 'is an ARMSTRONG number')
    else:
        print(input_num, 'is NOT an armstrong number')

except ValueError:
    print("That's not a valid number, Try Again !")

Output :

 

Program on GitHub

Feel free to check some of the other posts here.

Similar Programs :

• Checking Armstrong number in C
• Checking Armstrong number in C++
• Checking Armstrong number in Java